# Line slope calculator x-8y=1

**Straight line given by points A[1; 0] and B[9; 1]**

## Calculation:

**Slope-intercept form of line:**y = 0.125x-0.125

**Canonical form of the line equation:**x-8y-1 = 0

**Parametric form of the line equation:**

x = 8t+1

y = t ; t ∈ R

**Slope:**m = 0.125

**Slope angle of line: φ =**7°7'30″ = 0.1244 rad

**X intercept:**x

_{0}= 1

**Y intercept:**y

_{0}= q = -0.125

**Distance line from the origin:**d

_{0}= 0.124

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(8; 1)

**Normal vector: n =**(1; -8)

**Midpoint of the segment AB: M =**[5; 0.5]

**Perpendicular Bisector equation:**8x+y-40.5 = 0

**Vector OA = (1; 0) ; |OA| = 1**

**Vector OB = (9; 1) ; |OB| = 9.0554**

**Scalar product OA .OB = 9**

**Angle ∠ AOB = 6°20'25″ = 0.1107 rad**